SOLUTION: Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
csc θ = − 2√3/3
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Question 768308: Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
csc θ = − 2√3/3
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
csc θ = − 2√3/3
sinθ=1/cscθ=-3/2√3=-3√3/6=-√3/2
θ=4π/3 and 5π/3 (in Q3 and Q4 where sin and csc are<0)
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