SOLUTION: Find all solutions in [0,2pi] where sin^2(t)-cos^2(t)=0
Algebra.Com
Question 762218: Find all solutions in [0,2pi] where sin^2(t)-cos^2(t)=0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Substitute from the Pythagorean Identity:
Simplify
Take the root
Then all you have to do is find the four angles in
where the cosine of the angle is either
.
John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
Find all the solutions t in the interval (0, 2pi) to the equation
sin (2t) = sqare root (answered by lwsshak3)
Find all solutions t in the interval [0 , 2pi] to the equation sin(2t) = square root of 2 (answered by lwsshak3)
find all solutions t in the interval (0, 2pi) to the equation sin(2t)=square root of 2... (answered by stanbon)
Solve for t in the interval [0, 2pi)
cos^2(t)-sin^2(t)=0
(answered by stanbon)
Find all t in the interval [0, 2pi] satisfying 2(sin t)2 + 3 sin t + 1 =... (answered by Alan3354)
Solve cos^2 ( t ) = − 7 sin ( t ) for all solutions 0 ≤ t < 2... (answered by Alan3354)
Find all solutions of each of the equations in the interval (0, 2pi)
cos(x- pi/2) +... (answered by lwsshak3)
Use an addition or subtraction formula to find the solutions (in radians) of the equation (answered by shree840)
Find all solutions in the interval [0, 2pi) for the equation... (answered by jim_thompson5910)