SOLUTION: find all real values of θ in the interval [0°,360°) that satisfy the equation
4sin^4θ - 5sin^2θ+1=0.
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Question 759939: find all real values of θ in the interval [0°,360°) that satisfy the equation
4sin^4θ - 5sin^2θ+1=0.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find all real values of θ in the interval [0°,360°) that satisfy the equation
4sin^4θ - 5sin^2θ+1=0.
let u=sin^2(x)
u^2=sin^4(x)
..
4u^2-5u+1=0
(4u-1)(u-1)=0
..
u=1=sin^2(x)
sin(x)=±1
x=90º, 270º
..
u=1/4=sin^2(x)
sin(x)=±1/2
x=π/6, 5π/6, 7π/6, 11π/6
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