SOLUTION: point A(-a,b) is in quadrant ii and lies on the terminal arm of angle in standard position. Point B is the point of the terminal arm of angle and the unit circle centered at (O.O)

Question 759761: point A(-a,b) is in quadrant ii and lies on the terminal arm of angle in standard position. Point B is the point of the terminal arm of angle and the unit circle centered at (O.O) Determine the x-coordinate of B IN TERM OF a and b.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
I constructed OAP and OBQ as right triangles.
and
The Pythagorean theorem says that
Since OAP and OBQ have the same angle at O, and a angle, they are similar right triangles.
Since they are similar, corresponding sides are proportional.
So and
We know the lengths of the sides of OAP (AP, OP, and OA).
We know because it is the radius of the unit circle.
We can find the length of sides OQ and BQ:
means -->
means -->
The x-coordinate of B is .
The y-coordinate of B is .
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