SOLUTION: find the smallest positive angle for which sinx - cosx = 0 for x greater than 0 and less than 2 pie. I need a proper solution.

Algebra.Com
Question 756604: find the smallest positive angle for which sinx - cosx = 0 for x greater than 0 and less than 2 pie. I need a proper solution.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find the smallest positive angle for which sinx - cosx = 0 for x greater than 0 and less than 2 pie. I need a proper solution.
----
sin(x) = cos(x)
Smallest value for "x" is pi/4 or 45 degrees.
==================================
Cheers,
Stan H.

RELATED QUESTIONS

Please help me solve this equation:cosx+sinx=1/(cosx+sinx) for value of x such that{{{0... (answered by Fombitz)
Solve 2 sinx + cos2x = 2sin.sinx - 1 for 0 less thAN or equal and x greater than or equal (answered by jsmallt9)
The smallest positive number for which sin(2x)−sinx=0 is x= (answered by Alan3354)
I need help finding the solutions for this question. Find all solutions in the interval... (answered by lwsshak3)
Solve: cosx=sinx, 0 greater than or equal to x greater than or equal to... (answered by ewatrrr)
Given {{{ sinx=3/4 }}} and secx is less than 0, find cosx and... (answered by solver91311,Ryan O)
Solve for x on the interval given: a) 2sin^2x-5cosx+1=0 [0, pie] b) sinx/2=0 [-pie,... (answered by Alan3354)
i)- Solve the following equations for 0° < x < 360°. a) 2sinx cosx = 3 sinx b) (answered by Fombitz)
Determine all the values where sinx=√3 cosx for 0^0 ≤x ≤360°. I need steps... (answered by ikleyn)