SOLUTION: solve the following equation for all angles in [0,2pi) sin(2x-pi/3)= square root 3/2

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Question 756385: solve the following equation for all angles in [0,2pi)
sin(2x-pi/3)= square root 3/2
Answer by lwsshak3(11628) About Me  (Show Source):
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solve the following equation for all angles in [0,2pi)
sin(2x-pi/3)= square root 3/2
2x-π/3=π/3, 2π/3 (in Q1 and Q2 where sin>0)
..
2x-π/3=π/3
2x=2π/3
x=π/3
..
2x-π/3=2π/3
2x=3π/3=π
x=π/2