SOLUTION: Please help me
Solve the following equation for x, if 0 ≤ x ≤ 2π
a) 2cosēθ + cosθ - 1 = 0
b) sinēθ - sinθ = 0
c) √58cos(_
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Question 750034: Please help me
Solve the following equation for x, if 0 ≤ x ≤ 2π
a) 2cosēθ + cosθ - 1 = 0
b) sinēθ - sinθ = 0
c) √58cos(θ + 0.78) = -6
Thanks
Found 2 solutions by lwsshak3, josgarithmetic:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve the following equation for x, if 0≤ x ≤ 2π
a) 2cosēθ + cosθ - 1 = 0
(2cosx-1)(cosx+1)=0
cosx=1/2
x=π/3, 5π/3
or cosx=-1
x=π
..
b) sinēθ - sinθ = 0
sinx(sinx-1)=0
sinx=0
x=0,π
sinx=1
x=π/2
..
c) √58cos(θ + 0.78) = -6
cos(x+.78)=-6/√58≈-0.79
cos^-1(-0.79)≈2.48 in Q2
x+.78=2.48
x=2.48-.78=1.7
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Look at #a.
First, let , then
or
Reverse the substitution.
or
or , or also
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