SOLUTION: What are the x's of: ((sin^2)x) +(cos)x) +1)) = 0

Algebra.Com
Question 747131: What are the x's of: ((sin^2)x) +(cos)x) +1)) = 0
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
What are the x's of: ((sin^2)x) +(cos)x) +1)) = 0




(cos(x)-2)(cos(x)+1)=0
cos(x)=2 (reject,(-1 ≤ cosx ≤ 1)
cos(x)=-1
x=π

RELATED QUESTIONS

What are the x's of: ((sin^2)x) +(cos)x) +1)) =... (answered by KMST)
what will be the determinant of |1 0 0 | |2 cos x sin x | |3 sin x cos x... (answered by ikleyn)
if (sin x) + (cos x) = 1.2, what is the value of (sin^3 x) + (cos^3... (answered by MathLover1)
solve the equation: sin x(sin x + 1) = 0 4 cos^2 x - 1 =... (answered by ewatrrr)
solve the equation: sin x(sin x + 1) = 0 4 cos^2 x - 1 =... (answered by ewatrrr)
Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)
Find the solution of the equation for [0,2pi] 2(tan(theta))-(sec^2(theta))=0 Here... (answered by Alan3354)
Express the follolwing in terms of x {x>0}... (answered by stanbon)
what is the solution set of all angles in [0,2pi) 4 cos^2x-3=0 5 sec^2x-20=0 (answered by stanbon)