SOLUTION: Find the a(sub2) in the arithmetic sequence where a(sub5) = 42 and a(sub10) = 62.

Question 74356: Find the a(sub2) in the arithmetic sequence where a(sub5) = 42 and
a(sub10) = 62.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the a(sub2) in the arithmetic sequence where a(sub5) = 42 and
a(sub10) = 62.
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a(10)= a(1)+9d = 62
a(5) = a(1)+4d = 42
Subtract a(5) from a(10) to get:
5d=20
d=4
If d=4 substitute into a(1)+9d=62 to solve for a(1)
a(1)+9*4=62
a(1)+36=62
a(1) = 26
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Now find a(2)
a(2) = a(1) + (1)d
a(2) = 26 + 4
a(2) = 30
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Cheers,
Stan H.

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