SOLUTION: Find the value of x where 201, x, 1089 are three consecutive terms in a geometric sequence.
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Question 74069: Find the value of x where 201, x, 1089 are three consecutive terms in a geometric sequence.
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
(201x)x=1089
201x^2-1089=0
using the quadratic equation
we get
x=(0+-sqrt[0^2-4*201*-1089])/2*201
x=(+-sqrt875556)/402
x=(+-935.71)/402
x=935.71/402
x=2.32764 answer
proof
201*2.32764=468
468*2.32764=1089
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