SOLUTION: Find the exact value of sin^-1(-sqrt3/2). a.2sin(4t)cos(2t) b.2cos(4t)sin(2t) c.2cos(4t)cos(2t) d.2sin(4t)sin(2t) Than you for you help

Question 73916This question is from textbook
: Find the exact value of sin^-1(-sqrt3/2).
a.2sin(4t)cos(2t)
b.2cos(4t)sin(2t)
c.2cos(4t)cos(2t)
d.2sin(4t)sin(2t)
Than you for you help

This question is from textbook

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the exact value of sin^-1(-sqrt3/2).
a.2sin(4t)cos(2t)
b.2cos(4t)sin(2t)
c.2cos(4t)cos(2t)
d.2sin(4t)sin(2t)
----------
You want the angle whose sine is (-sqrt3)/2
Draw the angle:
y=-sqrt3
r= 2
--------
That angle is in the 4th quadrant.
The reference angle is 60 degrees.
That is the angle theta= 300 or theta = -60 degrees in the 4th Quadrant.
========
Cheers,
Stan H.
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