SOLUTION: use the half angle identities to find all solutions in the interval [0,2pi) sin^2x=cos^2(x/2)

SOLUTION: use the half angle identities to find all solutions in the interval [0,2pi) sin^2x=cos^2(x/2)

Algebra.Com

Question 738948: use the half angle identities to find all solutions in the interval [0,2pi) sin^2x=cos^2(x/2)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
use the half angle identities to find all solutions in the interval [0,2pi) sin^2x=cos^2(x/2)
***

..
2cos(x)-1=0
cos(x)=1/2
x=π/3, 5π/3
..
cos(x)+1=0
cos(x)=-1
x=π
RELATED QUESTIONS
Find all solutions of each of the equations in the interval (0, 2pi) cos(x- pi/2) +... (answered by lwsshak3)

Find all the solutions t in the interval (0, 2pi) to the equation sin (2t) = sqare root (answered by lwsshak3)

Find all solutions of the equation in the interval [0, 2pi).... (answered by Alan3354)

Use a graphing utility to approximate the solutions of the equation in the interval[0,... (answered by Fombitz)

Find all solutions t in the interval [0 , 2pi] to the equation sin(2t) = square root of 2 (answered by lwsshak3)

find all solutions t in the interval (0, 2pi) to the equation sin(2t)=square root of 2... (answered by stanbon)

Find all solutions in the interval [0, 2pi) Cos^2 (x/2) = cos^2... (answered by lwsshak3)

Find all solutions in the interval [0, 2pi) for the equation... (answered by jim_thompson5910)

could you help me find all the solutions in the interval [0, 2pi)... (answered by lwsshak3)