SOLUTION: how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being 2*radical 3/2. Any help wo

SOLUTION: how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being 2radical 3/2. Any help wo

Question 735749: how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being
2*radical 3/2. Any help would be greatly appreciated :)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being
2*radical 3/2. Any help would be greatly appreciated :)
-------------
sin(600) = 2sin(300)cos(300) **** not sin(600)....
= 2*(-sqrt(3)/2)*(1/2)
=

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