SOLUTION: Two ships leave San Francisco at the same time. One travels N 40 W at a speed of 20 knots. The other travels S 10 W at a speed of 15 knots. How far apart are they after 11 hours? (
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Question 717432: Two ships leave San Francisco at the same time. One travels N 40 W at a speed of 20 knots. The other travels S 10 W at a speed of 15 knots. How far apart are they after 11 hours? ( 1 knot= 1 nautical mile per hour)
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The distance from starting point of the mostly northward ship is 20*t, and the distance from starting point of the mostly southward ship is 15*t. If my understanding of the directions are correct, the angle of the two distance sides is degrees. N 40 W may be 50 degrees northward from West and S 10 W may be 80 degrees southward from West. So I guess, the angle at starting point is degrees.
A figure should be shown, but that is a long process here for me, yet I can feel a use for Law of Cosines. Using D for how far apart at 11 hours, the other side of the triangle, , and we want to finally let .
, and LET .
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