SOLUTION: what is the exact value of csc(tan^-1(-0.62))

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Question 708067: what is the exact value of
csc(tan^-1(-0.62))

Answer by Edwin Parker(36)   (Show Source): You can put this solution on YOUR website!
csc[tan-1(-0.62)]

The inverse tangent of a negative number is a negative angle
in the fourth quadrant.  The cosecant of an angle in the fourth 
quadrant is negative.  So the answer will be negative.

Let ϴ = tan-1(-0.62)

Then  

csc[tan-1(-0.62)] = csc(ϴ) 

So we want csc(ϴ)

tan(ϴ) = -0.62 =  = 

cot(ϴ) =  = 

We use 

cscē(ϴ) = 1 + cotē(ϴ) 

cscē(ϴ) = 1 + 

cscē(ϴ) = 1 + 

cscē(ϴ) =  + 

cscē(ϴ) = 

Take square roots of both sides.  And since we know
the answer is negative, we take the negative square root:

 csc(ϴ) = 

 csc(ϴ) = 

Edwin

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