SOLUTION: Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).

SOLUTION: Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).

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Question 69280: Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).
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2sin(2x) = sqrt(3)
sin(2x) = [sqrt(3)]/2
2x=(pi/3 or (2/3)pi)
x=(pi/6 or pi/3)
Cheers,
Stan H.
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