SOLUTION: solve the following equation for θ of 0° and 360°
3sin^2θ + sinθ=0
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Question 692002: solve the following equation for θ of 0° and 360°
3sin^2θ + sinθ=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve the following equation for θ of 0° and 360°
3sin^2θ + sinθ=0
sinθ(3sinθ+1)=0
sinθ=0
θ=0 and 180º
..
3sinθ+1=0
sinθ=-1/3
reference angle≈19.47º
θ≈199.47º and 340.53º (In quadrants III and IV where sin<0)
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