SOLUTION: solve 3cos^2 (theta) + sin(theta) =3 for theta between 0 and 360 degree.

Question 691486: solve 3cos^2 (theta) + sin(theta) =3 for theta between 0 and 360 degree.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve 3cos^2 (theta) + sin(theta) =3 for theta between 0 and 360 degree.
**
use x for theta
3cos^2x+ sinx =3
3(1-sin^2x)+sinx-3=0
3-3sin^2x+sinx-3=0
3sin^2x+sinx=0
sinx(3sinx+1)=0
..
sinx=0
x=0, π
..
3sinx+1=0
sinx=-1/3
reference angle≈19.47�
x≈199.47� and 340.53� (in quadrants III and IV where sin <0)
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