SOLUTION: Solve the equation in the interval [0, 2pi.) 2 cos2 θ = 2 − cos 2θ I think I'm supposed to use either a double or half- angle formula, but I'm not positive..

Question 691270: Solve the equation in the interval [0, 2pi.) 2 cos2 θ = 2 − cos 2θ
I think I'm supposed to use either a double or half- angle formula, but I'm not positive..
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve the equation in the interval [0, 2pi.)
2 cos2 θ = 2 − cos 2θ
----
2cos(2x) = 2 - cos(2x)
----
3cos(2x) = 2
cos(2x) = 2/3
2x = cos^-1(2/3)
2x = 0.7859
x = 0.3929
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Cheers,
Stan H.
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SOLUTION: Solve the equation in the interval [0, 2pi.) 2 cos2 &#952; = 2 &#8722; cos 2&#952; I think I'm supposed to use either a double or half- angle formula, but I'm not positive..

SOLUTION: Solve the equation in the interval [0, 2pi.) 2 cos2 θ = 2 − cos 2θ I think I'm supposed to use either a double or half- angle formula, but I'm not positive..