SOLUTION: Solve sin 2x = sin x for x between 0 and 2pi.

Question 690974: Solve sin 2x = sin x for x between 0 and 2pi.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve sin 2x = sin x for x between 0 and 2pi.
----
2sin(x)cos(x) = sinx
---
2sin(x)cos(x)-sin(x) = 0
----
Factor:
sin(x)[2cos(x)-1) = 0
sin(x) = 0 or cos(x) = 1/2
----
x = 0, or 2pi or pi/3 or (5/3)pi
------------------------------------
cheers,
Stan H.
==================
RELATED QUESTIONS
What are the solutions for sin(4x) + sin(x) between 0 and... (answered by Alan3354)

Find all the solutions between 0 and 2pi to the equation... (answered by ewatrrr)

Solve on the interval [0, 2pi] Sin*2x - sin x + 1=... (answered by lwsshak3)

sin (2x) = cos (2x) between (0,... (answered by Alan3354)

Solve all equations for (0, 2pi) sin(x + (pi/4)) + sin(x - (pi/4)) = 1 (answered by lwsshak3)

Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =<... (answered by lwsshak3)

Can you please help me solve this equation: {{{ sin(x+1)=cos(x) }}} with answers between... (answered by ikleyn)

solve for x sin(-4x)sin(-2x)=0 (answered by MathLover1)

0Sin^2(x)-sin(x)= Find the possible solutions between 0 and... (answered by Cromlix)