SOLUTION: Solve the equation on the interval [0,2pi), sin(2(x)+pi/6) = 1/2

SOLUTION: Solve the equation on the interval [0,2pi), sin(2(x)+pi/6) = 1/2

Algebra.Com

Question 686327: Solve the equation on the interval [0,2pi), sin(2(x)+pi/6) = 1/2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve the equation on the interval [0,2pi),
sin(2(x)+pi/6) = 1/2
sin^-1(1/2)=π/6
2x+π/6=π/6
2x=0
x=0
RELATED QUESTIONS
Solve the equation on the interval [0, 2pi). tan^2 x sin x = tan^2 x B.pi/2 , pi (answered by ikleyn)

Solve the equation sin(20)=1/2 on the interval... (answered by stanbon)

Solve equation, sin(2x) - sinx - 2cosx + 1 = 0, on the interval 0 < or equal x <... (answered by Boreal)

Please solve the equation for the interval [0, 2pi]: {{{2sin^2(x)-sin(x)-1=0}}}... (answered by josgarithmetic)

Solve 2 sin^2 x + cos x -2=0 on the interval -pi< x <... (answered by lwsshak3)

Solve the equation on the interval 0 < theta < 2pi cos^2 theta-sin^2 theta+sin... (answered by tarungehlot)

Solve on the interval [0, 2pi] Sin*2x - sin x + 1=... (answered by lwsshak3)

Solve the following equation on the interval [0, 2pi] cos^2 x + 2 cos x + 1 =... (answered by josgarithmetic)

Solve on the interval from 0 to pi:2cos^2 x-3 sin... (answered by lwsshak3)