SOLUTION: (tanx)/(cscx-cotx)-(sinx)/(cscx+cotx)=secx+cosx

Question 685442: (tanx)/(cscx-cotx)-(sinx)/(cscx+cotx)=secx+cosx
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

LCD = (cscx-cotx)(cscx+cotx)

((tanx*cscx+tanx*cotx)-(sinx*cscx-sinx.cotx))/(csc^2x-cot^2x)

((1/cosx)+1)-(1-cosx))/1

(1/cosx)+1-1+cosx)
(1/cosx)+cosx
= secx + cosx

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