SOLUTION: For each right triangle find all the missing values of the side lengths and angle measures.Show your work
a) Triangle PQR is right angled at Q , PQ is 24 cm, RQ is 10 cm , PQ is
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Question 684328: For each right triangle find all the missing values of the side lengths and angle measures.Show your work
a) Triangle PQR is right angled at Q , PQ is 24 cm, RQ is 10 cm , PQ is the hypotenuse which is unknown.
b) Triangle PRQ is right angled at R, PQ is 30 mm , RQ is 40 mm , PQ is 50 mm.
c) Triangle QRP is right angled at R , angle of P is 60 degrees, QP is 20 cm.
can you please explain this to me? thanks in advance
d) Triangle PQR is right angled at Q , QR is 1.125 dm, PR is 5.125 dm.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
For each right triangle find all the missing values of the side lengths and angle measures.Show your work
a) Triangle PQR is right angled at Q , PQ is 24 cm, RQ is 10 cm , PQ is the hypotenuse which is unknown.
PQ = sqrt[24^2+10^2] = sqrt(576] = 26
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b) Triangle PRQ is right angled at R, PQ is 30 mm , RQ is 40 mm , PQ is 50 mm.
P is the angle opposite RQ
PQ is opposite R and is the hypotenuse
So P = sin^-1(40/50) = 53.13 degrees
And Q = sin^-1(30/50) = 36.87 degrees
-----------------------------
c) Triangle QRP is right angled at R , angle of P is 60 degrees, QP is 20 cm.
can you please explain this to me? thanks in advance
Draw the picture.
You have a right triangle with
hypotenuse is side opposite right angle R which is QP = 20 cm
P = 60 degrees is the angle opposite QR
Q = 90-60 = 30 degrees
------
QR is side opposite P, so sin(P) = QR/QP ; sin(60) = QR/20 ;
QR = 20*sin(60) = 17.32
PR is side opposite Q which is 30 degrees
PR = (1/2)*hypotenuse = (1/2)*20 = 10 cm
--------------------------------
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d) Triangle PQR is right angled at Q , QR is 1.125 dm, PR is 5.125 dm.
Draw the picture and see if you can determine:
angle P =
angle R =
side PQ =
=================
Cheers,
Stan H.
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