SOLUTION: find the exact value of sec theta and cot theta let be an angle in quadrant IV such that sin theta= -3/5

Question 681748: find the exact value of sec theta and cot theta let be an angle in quadrant IV such that sin theta= -3/5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the exact value of sec theta and cot theta let be an angle in quadrant IV such that sin theta= -3/5
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If sin(theta) = -3/5 in QIV, then y = -3 and r = 5
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Solve for "x":
x^2 = r^2-y^2
x^2 = 25-9 = 16
x = 4
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So,
sec theta in QIV = r/x = 5/4
And
cot theat = QIV = x/y = -4/3
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Cheers,
Stan H.
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