SOLUTION: i have got up to this point sin 42=x/103 but i have no clue where to go from here can you help?
Algebra.Com
Question 671338: i have got up to this point sin 42=x/103 but i have no clue where to go from here can you help?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
i have got up to this point sin 42=x/103 but i have no clue where to go from here can you help?
---------
sin 42=x/103
x = 103*sin(42)
x =~ 68.92 (assuming it's 42 degrees)
RELATED QUESTIONS
sqrt(6)(sqrt(3)-2)]
Add or subtract as indicated
I have gotten to this point:... (answered by ankor@dixie-net.com)
I have no clue even where to begin this!!!... (answered by Jeff Gordon)
Hello! I wish I could say that I started on this problem but I have no clue what to do.... (answered by josmiceli,KMST)
This is proving a trigonometric equation.
Verify cos(x))/(1-sin(x))=sec(x)+tan(x)... (answered by jim_thompson5910)
These quadratics are killing me. Can you help me with this one?
(x+2)(x+3)=(x+7)(x-4)
(answered by josgarithmetic)
Hello, I need to solve this equation. If there is no solution I have to say so.
5/4x + (answered by stanbon)
Could you please help me with this problem? It's using perfect triangles and the sine... (answered by ewatrrr)
I dont know what section I need, but can someone help me with the following problem? I... (answered by stanbon)
What is the answer to x^2+6*x=16
I got to the point where I moved the "16" to the left... (answered by richwmiller)