SOLUTION: 3X^2-13X+14/4X * 12X^2/X^3-2X^2 / 9X-21/6 i know you keep change flip to get 3X^2-13X+14/4X * 12X^2/X^3-2X^2 * 6/9X-21 then u factor (which this is probably where i went wrong)

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Question 666109: 3X^2-13X+14/4X * 12X^2/X^3-2X^2 / 9X-21/6
i know you keep change flip to get
3X^2-13X+14/4X * 12X^2/X^3-2X^2 * 6/9X-21
then u factor (which this is probably where i went wrong) and get
(3X-6)(3X-7)/4X * 12X^2/X^2(X-2) * 6/3(3X-7)
then u are suposed to reduce any from top to bottom but all i can get rid of are the (3X-7)s
but then i still have a ton on the tops and bottomes so im not shure where to go from here with multiplying the tops and bottomes so if someone could help it would be much apreshiated thanks
Found 2 solutions by ewatrrr, swincher4391:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,





Take a look and finish Up 

Answer by swincher4391(1107)   (Show Source): You can put this solution on YOUR website!
 

So turn everything into multiplication by flipping (9x-21)/6









Now factor everything







Combine numerator and denominators:







Cancel stuff:







So we're left with 



Divide through the 12 into the 72 to get:







 

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