SOLUTION: Find the remaining trigonometric ratios.
cos(x) = − 1/7, π < x < 3π/2
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Question 654208: Find the remaining trigonometric ratios.
cos(x) = − 1/7, π < x < 3π/2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the remaining trigonometric ratios.
cos(x) = − 1/7, π < x < 3π/2
**
you are working with a reference angle and right triangle in quadrant III
cos=-1/7=adj side/hypotenuse
opp side=-√(7^2-1^2)=-√(49-1)=-√48
..
trigonometric ratios:
sin(x)=-√48/7
cos(x)=-1/7
tan(x)=√48
csc(x)=-7/√48
sec(x)=-7
cot(x)=1/√48
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