SOLUTION: , find all the values of Θ, if Θ is in the interval [0�, 360�] and has the given function value sin Θ=- sqrt(3)/2

SOLUTION: , find all the values of Θ, if Θ is in the interval [0�, 360�] and has the given function value sin Θ=- sqrt(3)/2

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Question 653614: , find all the values of Θ, if Θ is in the interval [0�, 360�] and has the given function value
sin Θ=- sqrt(3)/2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find all the values of Θ, if Θ is in the interval [0�, 360�] and has the given function value
sin Θ=- sqrt(3)/2
Θ=240� and 300� (in quadrants III and IV where sin<0)
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