SOLUTION: I need to prove that the (x = theta) (sin x/1-cos x)-(1+cos x)/sin x) = 0
Can I multiply the left by (sin x/sin x) and the right side by (1-cos x/ 1-cos x)?
WHen I do this I e
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Question 647847: I need to prove that the (x = theta) (sin x/1-cos x)-(1+cos x)/sin x) = 0
Can I multiply the left by (sin x/sin x) and the right side by (1-cos x/ 1-cos x)?
WHen I do this I end up with
sin squared x - (1-cos squared x) over sin (1-cos x)
since I know that sin squared + cos squared = 1 and 1-1 = 0 over the sin (1-cos x) I think I have proved that 0 = 0
Please advice if my logic is incorrect
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!
I need to prove that the (x = theta) (sin x/1-cos x)-(1+cos x)/sin x) = 0
Can I multiply the left by (sin x/sin x) and the right side by (1-cos x/ 1-cos x)?
WHen I do this I end up with
sin squared x - (1-cos squared x) over sin (1-cos x)
since I know that sin squared + cos squared = 1 and 1-1 = 0 over the sin (1-cos x) I think I have proved that 0 = 0
Please advice if my logic is incorrect
As seen the LCD that you need to multiply equation by is: sin x (1 - cos x) to get:
sin^2 x - (1 - cos^2 x) = 0
Since 1 - cos^2 x = sin^2 x, then sin^2 x - (1 - cos^2 x) = 0 becomes:
sin^2 x - sin^2 x = 0
(proven)
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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