SOLUTION: y=sin(4x+pi/7)
what is the phase shift
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Question 647687: y=sin(4x+pi/7)
what is the phase shift
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
The phase shift is that value of x that makes the argument of the sine function equal to zero. In your case we have to solve for x when
(1) 4*x + pi/7 = 0 or
(2) x = - pi/28 rad
or since pi rad = 180 deg we have
(3) x = - 180/28 deg
(4) x = -45/7 deg
The phase shift is approximately -6.43 degrees. At this value of x you have sin(4x+pi/7) = o. That is, the sine wave crosses the x-axis at approx -6.43 degrees instead of at x = zero. Hence there is a shift of the sinwave to the left by 6.43 degrees. Get it?
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