SOLUTION: If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta. Please help! I've been attempting this for over an hour and I can't get a correct answer!

Question 641274: If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta.
Please help! I've been attempting this for over an hour and I can't get a correct answer!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
If csc=-5/3 on the interval (pi, 3pi/2), find the exact value of tan2beta.
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csc = -5/3 --> sin = -3/5
b in the Q3
cos = -4/5
----
sin(2b) = 2sin*cos = 24/25
cos(2b) = 7/25
tan(2b) = sin/cos = 24/7

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