SOLUTION: Find all values of x such that sin 2x = sin x and 0 is less than or equal to x which is less than or equal to 2 pi.
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Question 640256: Find all values of x such that sin 2x = sin x and 0 is less than or equal to x which is less than or equal to 2 pi.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ \sin\left(x\right))
Use the double angle formula:
cos(x)\ =\ \sin(x))
Multiply both sides by })
\ =\ 1)
\ =\ \frac{1}{2})
Use the unit circle to find the two values of 
that result in \ =\ \frac{1}{2})
in the specified interval (once around the circle). Remember, )
is the coordinate of the point of intersection of the terminal ray and the unit circle.
John
My calculator said it, I believe it, that settles it
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