SOLUTION: Could you help me solve (sinx+the square root of 3=-sinx) for all solutions 0<x<2pi
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Question 640212: Could you help me solve (sinx+the square root of 3=-sinx) for all solutions 0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ +\ \sqrt{3}\ =\ -\sin(x))
\ =\ -\sqrt{3})
\ =\ -\frac{\sqrt{3}}{2})
Use the unit circle to find the two values of 
for which \ =\ -\frac{\sqrt{3}}{2})
. Remember, the sin is the 
coordinate of the intersection of the terminal ray of the angle with the unit circle.
John
My calculator said it, I believe it, that settles it
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