SOLUTION: If sin x=4/5 and pi/4 < x <pi/2 , Find sin(4x).

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Question 639483: If sin x=4/5 and pi/4 < x Find sin(4x).
Answer by AnlytcPhil(1810)   (Show Source): You can put this solution on YOUR website!
sin x=4/5 and pi/4 < x < pi/2 ,
Find sin(4x)
Use the identity sin(2@) = 2sin(@)·cos(@) where @ = 2x

sin(4x) = sin[2(2x)] 

sin(4x) = 2sin(2x)·cos(2x)

Use that identity again with @=x to replace sin(2x).  Use
the identity cos(2@) = cosē(@)-sinē(@) to replace cos(2x)

sin(4x) = 2[2sin(x)·cos(x)][cosē(x)-sinē(x)]

sin(4x) = 4sin(x)·cos(x)[cosē(x)-sinē(x)] 

We have sin(x) =  but we don't have cos(x).  We use the identity
sinē(@)+cosē(@)=1 by solving it for cos(@)
        cosē(@)=1-sinē(@)
        cosē(x)=1-()ē = 1- =  = 
         cos(x)=
         cos(x)=
Sinve we are given that  < x < , we know that
the cosine is positive, therefore
         cos(x)=

sin(4x) = 4sin(x)·cos(x)[cosē(x)-sinē(x)]
sin(4x) = 4([-]
sin(4x) = [-]
sin(4x) = []
sin(4x) = 

Edwin


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