SOLUTION: The directions are to solve each equation on the interval [0,2pi)
2. cos^2x=cos x
(cosine squared x)
Algebra.Com
Question 639141: The directions are to solve each equation on the interval [0,2pi)
2. cos^2x=cos x
(cosine squared x)
Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!
Use a property of zero
or
, or
, or
RELATED QUESTIONS
Solve the following equation on the interval [0, 2pi]
cos^2 x + 2 cos x + 1 =... (answered by josgarithmetic)
Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)
Solve cos(x/2)=-sinx on the interval 0 to... (answered by Alan3354)
Solve on the interval [0, 2pi]
Sin*2x - sin x + 1=... (answered by lwsshak3)
Solve each equation on the interval 0 (answered by lwsshak3)
Solve each equation on the interval (0,2pi): a.) 2sin^(2)x-cos x-1=0, b.) sin 3x cos 2x + (answered by lwsshak3)
Find all solutions of each of the equations in the interval (0, 2pi)
cos(x- pi/2) +... (answered by lwsshak3)
solve the equation, [0, 2pi)
a)... (answered by lwsshak3)
Solve the equation in the interval from 0 to 2pi.
3 cos 4theta =... (answered by ikleyn)