SOLUTION: If a+b = 90degree, Find max value of (sin a.sin b)

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Question 639116: If a+b = 90degree, Find max value of (sin a.sin b)
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
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Answer by Edwin McCravy(20064)   (Show Source): You can put this solution on YOUR website!
a+b = 90°
  b = 90°-a


sin(a)sin(b) = sin(a)sin(90°-a) = sin(a)cos(a)

We use the identity sin(2a) = 2sin(a)cos(a) by dividing both sides by 2

                     = sin(a)cos(a)

So

sin(a)sin(b) = sin(a)sin(90°-a) = sin(a)cos(a) =    

The maximum value of the sine function is 1

so the maximum value of  is 

Answer: 

Edwin
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