# SOLUTION: Hi, for the life of me I can not graph 2 periods for y=2sec3(x-pie/6) -1 I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculato

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Hi, for the life of me I can not graph 2 periods for y=2sec3(x-pie/6) -1 I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculato      Log On

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 Click here to see ALL problems on Trigonometry-basics Question 638585: Hi, for the life of me I can not graph 2 periods for y=2sec3(x-pie/6) -1 I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculator for I get the graph as a direct line going down. My mode is in radians too so it isn't that. I need to state the domain for that equation and I thought it would be all real numbers and that the range would be -3_< y_<1 and no idea how to determine the asymptotes. Please can you teach me? Thank youAnswer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!graph 2 periods for y=2sec[3(x-pie/6)] -1 I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculator for I get the graph as a direct line going down. My mode is in radians too so it isn't that. -- Comment: You were missing a some parentheses. ---------- I need to state the domain for that equation and I thought it would be all real numbers and that the range would be -3_< y_<1 and no idea how to determine the asymptotes. ---- Domain: All Real Numbers except where cosine = 0: 3(x-(pi/6)) = 0 x = pi/6 Note: that is also where you find a vertical asymptote. ---- 3(x-(pi/6)) = pi x-(pi/6) = pi/3 x = pi/2 Another vertical asymptote at this point. ============ Cheers, Stan H.