SOLUTION: Hi, for the life of me I can not graph 2 periods for y=2sec3(x-pie/6) -1 I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculato

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Hi, for the life of me I can not graph 2 periods for y=2sec3(x-pie/6) -1 I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculato      Log On

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Question 638585: Hi, for the life of me I can not graph 2 periods for
y=2sec3(x-pie/6) -1
I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculator for I get the graph as a direct line going down.
My mode is in radians too so it isn't that.
I need to state the domain for that equation and I thought it would be all real numbers and that the range would be -3_< y_<1
and no idea how to determine the asymptotes. Please can you teach me? Thank you
Answer by stanbon(57387) About Me  (Show Source):
You can put this solution on YOUR website!
graph 2 periods for
y=2sec[3(x-pie/6)] -1
I know that sec=1/cos but on paper im not sure how to do it, nor apparently on a graphing calculator for I get the graph as a direct line going down.
My mode is in radians too so it isn't that.
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Comment: You were missing a some parentheses.

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I need to state the domain for that equation and I thought it would be all real numbers and that the range would be -3_< y_<1
and no idea how to determine the asymptotes.
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Domain: All Real Numbers except where cosine = 0:
3(x-(pi/6)) = 0
x = pi/6
Note: that is also where you find a vertical asymptote.
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3(x-(pi/6)) = pi
x-(pi/6) = pi/3
x = pi/2
Another vertical asymptote at this point.
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Cheers,
Stan H.