SOLUTION: Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14
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Question 635545: Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14 miles per hour.
Approximate the distance between them at noon the same day. Round answer to two decimal places.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14 miles per hour.
Approximate the distance between them at noon the same day. Round answer to two decimal places.
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N46W = 314 degs
S55W = 235 degs
No one in the world uses N46W or S55W except the authors of math books who never go outside.
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The angle between their paths is 79 degs
The distances are 24 & 28 miles
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Use the Cosine Law
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