SOLUTION: Solve 2 sinx + cos2x = 2sin.sinx - 1 for 0 less thAN or equal and x greater than or equal than 2pi?
Algebra.Com
Question 634344: Solve 2 sinx + cos2x = 2sin.sinx - 1 for 0 less thAN or equal and x greater than or equal than 2pi?
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
"2sin.sinx"???
You'll need to re-post your problem with this part corrected/clarified.
RELATED QUESTIONS
Please help me solve this equation:cosx+sinx=1/(cosx+sinx) for value of x such that{{{0... (answered by Fombitz)
2 sin^2x+sinx=1
Find all solutions to each equation for 0 less than or equal too x... (answered by stanbon)
Solve: cosx=sinx, 0 greater than or equal to x greater than or equal to... (answered by ewatrrr)
4 sinx-3=5 for 0less than or equal x less than or equal 2 pi
(answered by Alan3354)
cos5xcos2x+sin5xsin2x= -1 for x is greater or equal to 0, and less than or equal to... (answered by Fombitz)
2sin^2x-3sinx+1=0, 0 equal to or less than x... (answered by fractalier)
if sinx=2/5, where 0 less than or equal to x less than or equal to 90°. without using... (answered by Alan3354)
solve 2sinx-1= 0 for 0 is less than or equal to x less than 2pi (answered by god2012)
Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)