SOLUTION: if sin a = 3/4 and cos b = 2/3 then tan a + cot b =?
i only got as far as tan a = 3/4:2/3
and cot b = 1/ (3/4:2/3)
i am obviously lost please help!
Algebra ->
Trigonometry-basics
-> SOLUTION: if sin a = 3/4 and cos b = 2/3 then tan a + cot b =?
i only got as far as tan a = 3/4:2/3
and cot b = 1/ (3/4:2/3)
i am obviously lost please help!
Log On
Question 631814: if sin a = 3/4 and cos b = 2/3 then tan a + cot b =?
i only got as far as tan a = 3/4:2/3
and cot b = 1/ (3/4:2/3)
i am obviously lost please help! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! if sin a = 3/4 and cos b = 2/3 then tan a + cot b =?
-------------
1st find the cos(a) and sin(b)
cos = sqrt(1 - sin^2) - sqrt(1 - 9/16)
cos(a) = sqrt(7)/4
---------------
find the sin(b) the same way.
-----
then it's tan = sin/cos, etc
