SOLUTION: solve the equation exactly over the interval [0,2pi)
cos 2x= sqrt2 -cos 2x
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Question 628662: solve the equation exactly over the interval [0,2pi)
cos 2x= sqrt2 -cos 2x
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve the equation exactly over the interval [0,2pi)
cos 2x= sqrt2 -cos 2x
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2cos(2x) = sqrt(2)
cos(2x) = sqrt(2)/2
2x = pi/4 or -pi/4
x = pi/8 or -pi/8
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Cheers,
Stan H.
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