SOLUTION: What values for q (0 � q < 2p) satisfy the equation? 2sqrt2sinq + 2 = 0

Question 627577: What values for q (0 � q < 2p) satisfy the equation?
2sqrt2sinq + 2 = 0
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!

First we solve for sin(q). Subtracting 2:

Divide both sides by :

Rationalizing the denominator:

Now we solve for q. We should recognize as a special angle value for sin. We should recognize that the reference angle will be . And since our sin is negative and since sin is negative in the 3rd and fourth quadrants, we know that q must terminate there, too, with a reference angle of
So
(for the third quadrant)
or
(for the fourth quadrant)
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