SOLUTION: Prove that: 1 + cos A/ 1 - cos A = tan�A/(secA

SOLUTION: Prove that: 1 + cos A/ 1 - cos A = tan�A/(secA - 1)�

Question 62235: Prove that:
1 + cos A/ 1 - cos A = tan�A/(secA - 1)�
Answer by kapilsinghi(68) (Show Source): You can put this solution on YOUR website!
1 + cos A/ 1 - cos A = tan�A/(secA - 1)�
LHS = (1 + cos A)/ (1 - cos A)
RHS = tan�A/(secA - 1)�
= [tanA/(sec-1)]^2
= [tanA/((1/cosA)-1)]^2
= [tanA/(1-cosA)/cosA]^2
= [(tanA*cosA)/(1-cosA)]^2
= [sinA/(1-cosA)]^2
= sinA^2/(1-cosA)^2
= (1-cosA^2)/(1-cosA)^2
= [(1-cosA)*(1+cosA)]/[(1-cosA)*(1-cosA)]
= (1+cosA)/(1-cosA)
LHS = RHS
Regards
Kapil
kapilsinghi123@gmail.com
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