SOLUTION: Could someone help me with this problem. g(x)=1-sin^(2)X where x is in radians the function of g can be changed so it can also be described as h(x)=a sin[b(x+(pi/4)]+d sta

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Could someone help me with this problem. g(x)=1-sin^(2)X where x is in radians the function of g can be changed so it can also be described as h(x)=a sin[b(x+(pi/4)]+d sta      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 62200: Could someone help me with this problem.
g(x)=1-sin^(2)X where x is in radians
the function of g can be changed so it can also be described as h(x)=a sin[b(x+(pi/4)]+d
state the values of a, b, c, d.
Thanks for your help.
Answer by stanbon(48558) About Me  (Show Source):
You can put this solution on YOUR website!
g(x)=1-sin^(2)X where x is in radians
the function of g can be changed so it can also be described as h(x)=a sin[b(x+(pi/4)]+d
state the values of a, b, c, d.
--------
The equivalent equation is:
y=(1/2)sin(2(x+pi/4))+(1/2)
a=(1/2), b=2, c is missing but it is pi/4, d=(1/2)
Cheers,
San H.