# SOLUTION: Find exact solutions over the indicated intervals (x real and theta in degrees) 2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Find exact solutions over the indicated intervals (x real and theta in degrees) 2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees      Log On

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 Question 619473: Find exact solutions over the indicated intervals (x real and theta in degrees) 2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degreesAnswer by lwsshak3(6512)   (Show Source): You can put this solution on YOUR website!Find exact solutions over the indicated intervals (x real and theta in degrees) 2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees ** 2sinx+5sinx-3=0 (2sinx-1)(sinx+3)=0 sinx+3=0 sinx=-3 (reject, -1 ≤ x ≤ 1) 2sinx-1 sinx=1/2 x=30º and 150º