SOLUTION: What is the period of the function y = 1/2 sin (x/3 - Pi)? (1) 1/2 (2) 1/3 (3) 2/3 Pi (4) 6 Pi the formula is period = 2pi/b. I tryed to solve it and

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: What is the period of the function y = 1/2 sin (x/3 - Pi)? (1) 1/2 (2) 1/3 (3) 2/3 Pi (4) 6 Pi the formula is period = 2pi/b. I tryed to solve it and      Log On

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 Click here to see ALL problems on Trigonometry-basics Question 613766: What is the period of the function y = 1/2 sin (x/3 - Pi)? (1) 1/2 (2) 1/3 (3) 2/3 Pi (4) 6 Pi the formula is period = 2pi/b. I tryed to solve it and I got 6/x....Answer by jim_thompson5910(28598)   (Show Source): You can put this solution on YOUR website!T = (2pi)/B T = (2pi)/(1/3) T = 2pi*3 T = 6pi -------------------------------------------------------------------------------------------------------------- If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim --------------------------------------------------------------------------------------------------------------