SOLUTION: What is the period of the function y = 1/2 sin (x/3 - Pi)?
(1) 1/2 (2) 1/3 (3) 2/3 Pi (4) 6 Pi
the formula is period = 2pi/b. I tryed to solve it and
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Question 613766: What is the period of the function y = 1/2 sin (x/3 - Pi)?
(1) 1/2 (2) 1/3 (3) 2/3 Pi (4) 6 Pi
the formula is period = 2pi/b. I tryed to solve it and I got 6/x....
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
T = (2pi)/B
T = (2pi)/(1/3)
T = 2pi*3
T = 6pi
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