SOLUTION: I am a grade 10 students and i like trigonometry but i found this quiet tough.Plz can u solve it for me.. prove that (sec4a-1)/(sec8a-1)=tan4a/tan2a

Question 61331: I am a grade 10 students and i like trigonometry but i found this quiet tough.Plz can u solve it for me..
prove that (sec4a-1)/(sec8a-1)=tan4a/tan2a
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
I am a grade 10 students and i like trigonometry but i found this quiet tough.Plz can u solve it for me..
prove that (sec4a-1)/(sec8a-1)=tan4a/tan2a
FEW THINGS , I WANT TO KNOW..
1.IN 10 TH. GRADE ARE YOU TAUGHT MULTIPLE ANGLES.ASSUMING SO..
2.HAVE YOU TYPED THE PROBLEM CORRECTLY?IT DOES NOT APPEAR SO..GOR EXAMPLE TRY FOR A=15 DEGREES
LHS = [SEC(60)-1]/[SEC(120)-1]= 1/-3=-1/3
RHS = TAN(60)/TAN(30)= SQRT(3)/[1/SQRT(3)]=3...
SO THE PROBLEM IS NOT CORRECT....
3.ANY WAY LET US KEEP LHS IN TACT AND FIND IT OUT INTERMS OF TAN MULTIPLE ANGLES
LHS =[{1-C0S(4A)}/{COS(4A)}]/[{1-COS(8A)}/{COS(8A)}]
= 2SIN^2(2A)*COS(8A)/[2SIN^2(4A)COS(4A)]
=[{2SIN^2(2A)COS(8A)}]/[{2SIN(4A)COS(4A)}{SIN(4A)}]
=[2SIN^2(2A)COS(8A)]/[{SIN(8A)}{2SIN(2A)COS(2A)}]
= TAN(2A)/TAN(8A)....IS THE ANSWER
OK? GOT IT?.
RELATED QUESTIONS
ok i have all the multiplying,and dividing fractions that look like this (answered by jim_thompson5910)

i need sum help on my math we are learning inequalities right now with greater than and... (answered by stanbon)

I would like 2 say thank u for helping me rite now it looks like this 7x to the... (answered by checkley77)

Hi i have a question on trigonometry that i am finding quite challenging: Prove that... (answered by robertb)

Hello my name Kenny Adams and I am having a problem that really dosent make since to me... (answered by stanbon,bucky)

2.)Why do we have to check the solutions when we solve radical equations? 4.)... (answered by edjones)

Hi, Can you please help me? . Quadratic Equations ( You solve this problem same as... (answered by checkley77)

I have been at this math problem for quiet a while now. I would really like it if you can (answered by stanbon,ankor@dixie-net.com)

Hello, I would like a formula that will solve for the base length of an isosceles... (answered by cleomenius)