SOLUTION: How do I solve the right triangle with these as given? C = 90degrees, c = 12, and A = 26degrees40minutes IThis is sorta a duplicate since the first question I forgot to add C

Question 611125: How do I solve the right triangle with these as given?
C = 90degrees, c = 12, and A = 26degrees40minutes
IThis is sorta a duplicate since the first question I forgot to add C = 90degrees. I'm sorry. Please someone answer this question. Thank you.
Found 2 solutions by scott8148, stanbon:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
a = c * sin(A)

b = c * cos(A)

B = C - A
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I solve the right triangle with these as given?
C = 90degrees, c = 12, and A = 26degrees40minutes
------------------
Draw the picture:
-----
B = 90 - (26 deg 40') = 63 deg 20'
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Solve for "a":
sin(A) = a/c
a = c*sin(A) = 12*sin(26.67 degree) = 5.386
----
b = c*cos(A) = 12*cos(26.67 degrees) = 10.72
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cheers,
Stan H.
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