SOLUTION: i cant get the answer for this one please help me. express cos 136 degrees as a function of a positive acute angle

Question 601229: i cant get the answer for this one please help me.
express cos 136 degrees as a function of a positive acute angle
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
express cos 136 degrees as a function of a positive acute angle
cos(136) = -sin(46)

Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!

The other tutor gave you a correct answer, but he gave it as a sine function of the complement of the reference angle, instead of a cosine function of the reference angle. I think you should express it as a cosine function of the reference angle, since you were given a cosine function, not change to different trig function. Rules for finding the reference angle: If an angle is between 0� and 90� (Quadrant I), the reference angle is the same as the angle. If an angle is between 90� and 180� (Quadrant II), to find the reference angle, subtract it from 180�. If an angle is between 180� and 270� (Quadrant III), to find the reference angle, subtract 180� from it. If an angle is between 270� and 360� (Quadrant IV), to find the reference angle, subtract it from 360�. So the reference angle for 136� (Quadrant II), is 180�-136� = 44� Since the cosine is negative in Quadrant II, the answer is -cos(44�) That is what I believe your teacher wants, not a sine function of the complement of the reference angle. Edwin

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